Matematika

Pertanyaan

nilai x yang memenuhi persamaan log(x2-1)-log(x-1)=1+log(x-8) adalah

1 Jawaban

  • log(x²-1) - log(x-1) = 1+log(x-8)
    log(x²-1)/(x-1) = 1+log (x-8)
    log (x+1)(x-1)/(x-1) = 1+log (x-8)
    log (x+1) - log(x-8) = 1
    log (x+1)/(x-8) = log 10
    (x+1)/(x-8) = 10
    x+1 = 10x - 80
    1+80 = 10x-x
    81 = 9x
    x = 9

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