jawab 1-2 besok di bawa

A.
[tex] \frac{3ab}{5} + \frac{4ab}{60} \\ = \frac{12 \times 3ab + 4ab}{60} \\ = \frac{36ab + 4ab}{60} \\ = \frac{40ab}{60} \\ = \frac{2ab}{3} \\ = \frac{2}{3} ab[/tex]

B.
[tex] \frac{127}{xy} - \frac{4}{x} \\ = \frac{127 - 4 \times y}{xy} \\ = \frac{127 - 4y}{xy} [/tex]
Maaf Kalau Salah