f(2x+a)=3x+4a dan f(a)=2 maka f(1)=

jawab

f(2x + a) = 3x + 4a

f(x) = 3 {1/2 (x - a)} + 4a
f(x) = 3/2 (x - a)  + 4a
f(x) = 3/2 x - 3/2 a + 4a
f(x) = 3/2 x + 5/2a
f(x) = 1/2 (3x + 5a)
f(a) = 2
1/2 (3a + 5a) = 2
4a = 2
a = 1/2

f(x) = 1/2 (3x + 5/2)
f(1) = 1/2 ( 3 + 5/2 ) 
f(1) = 1/2  ( 3 + 5/2)
f(1) = 1/2 (11/2)
f(1) = 11/4