persamaan linear 1, eliminasi kan 7x-y=8 3x+2y=6 2 , substitusi kan x-y=15 2x-3y=-3
Matematika
lezzeindah66
Pertanyaan
persamaan linear
1, eliminasi kan
7x-y=8
3x+2y=6
2 , substitusi kan
x-y=15
2x-3y=-3
1, eliminasi kan
7x-y=8
3x+2y=6
2 , substitusi kan
x-y=15
2x-3y=-3
2 Jawaban
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1. Jawaban subebe
7x - y = 8 (x3) 21x - 6y = 24
3x + 2y = 6 (x7) 21x + 14y = 42
-20 y = -18
y = -18/-20 = 9/10
7x - y = 8 (x2) 14x - 2y = 16
3x +2y = 6 (x1) 3x +2y = 6
17 x = 22
x = 22/17
2. x-y = 15
x = 15 +y
2x - 3y = -3
2(15+y) - 3y = -3
30 + 2y -3y = -3
30 - y = -3
y = 33
x = 15+33 = 48 -
2. Jawaban udink
1. persmaan 1 dikali 2 menjadi
14x - 2y = 16
3x + 2y = 6 +
17x = 22
x=22/17 maka y=7(22/17)-8=18/17
2. x-y=15 =====> x=15+y
2(15+y)-3y=-3
30 + 2y -3y = -3
-y = -3-30
y= 33 maka x= 15+33 = 48