Fisika listrik statis

Listrik Statis
> Hukum Coulomb

Q₁ = -4 μC = -4 x 10⁻⁶ C
Q₂ = 3 μC = 3 x 10⁻⁶ C
Q₃ = -8 μC = -8 x 10⁻⁶ C
r₃₂ = 20 cm = 2 x 10⁻¹ m
r₃₁ = 30 cm = 3 x 10⁻¹ m

F₃ = _ ?

F₃₁ = k Q₃ Q₁ / (r₃₁)²
F₃₁ = 9 x 10⁹ • 8 x 10⁻⁶ • 4 x 10⁻⁶ / (3 x 10⁻¹)²
F₃₁ = 32 x 10⁻¹ N
F₃₁ = 3,2 N [Tolak Menolak]

F₃₂ = k Q₃ Q₂ / (r₃₂)²
F₃₂ = 9 x 10⁹ • 8 x 10⁻⁶ • 3 x 10⁻⁶ / (2 x 10⁻¹)²
F₃₂ = 54 x 10⁻¹
F₃₂ = 5,4 N [Tarik Menarik]

Kedua gaya tersebut saling meniadakan , sehingga Resultannya :
F₃ = F₃₂ - F₃₁
F₃ = 5,4 - 3,2
F₃ = 2,2 N

Jawaban : B