x^2 + y^2 + 5x - 6y - 33 = 0 dititik (1,-3)

jawab

x² + y² + 5x  -6y - 33 = 0
2a = 5
a = 52

2b= -6
b = - 3

c= -33

titik (1,-3)
1² + (-3)² + 5(1) - 6(-3) - 33= 0
1+9+ 5+ 18 - 33=0
0= 0

persamaan garis singgung di titik (x1,y1)=(1, -3)
x1x + y1 y + a(x +x1) + b(y+y1) + c =0
1(x) + -3(y) + 5/2(x+1) -3(y- 3)  - 33 = 0
x - 3y + 5/2 x + 5/2 - 3y + 9 - 33 =0
7/2 x - 6y - 43/2 = 0 ...."kali 2

7x - 12y - 43= 0