tolong ya....pke cara.. mksih

[tex] \frac{2x^{2} - 8 }{4x - 2} \div \frac{4x - 8}{8x - 4} \\ = \frac{2x ^{2} - 8}{4x - 2} \times \frac{8x - 4}{4x - 8} \\ = \frac{2(x ^{2} - 4)}{2(2x - 1)} \times \frac{4(2x - 1)}{4(x - 2)} \\ = \frac{2(x - 2)(x + 2)}{2} \times \frac{4}{4(x - 2)} \\ = \frac{2(x + 2)}{1} \times \frac{2}{4} \\ = \frac{x + 2}{1} \times \frac{2}{2} \\ = x + 2[/tex]

Jawaban : c. x + 2

Maaf Kalau Salah