(x - 5)^2 + (y + 2)^2 = 5 dititik yang berordinat -4

lingkaran
(x-5)² +(y+2)² = 5
P(a,b)=(5,-2), r² = 5

ordinat y = - 4
(x-5)²+(-4+2)² = 5
(x-5)²+ 4= 5
(x-5)² = 1
x- 5 = 1 atau x - 5  = -1
x  = 6 atau x =  4

persamaan garis singgung di (x1,y1) pada ling P(a.b) , r
(x1-a) (x-a) + (y1-b)(y-b) = r²

di (6, -4)
(6-5)(x-5) + (-4+2)(y+2) = 5
x- 5 - 2(y+2) = 5
x - 5 - 2y - 4 = 5
x - 2y = 14

di(4,-4)
(4-5)(x-5) + (-4+2)(y+2) = 5
-(x-5 ) - 2(y+2) = 5
-x + 5 - 2y - 4 = 5
- x - 2y  + 1 = 5
- x  - 2y = 4
x + 2y = - 4