Operasi aljabar pada fungsi f (x) =2x-6 g (x) =x2-9
Matematika
nurmaya9098
Pertanyaan
Operasi aljabar pada fungsi f (x) =2x-6 g (x) =x2-9
1 Jawaban
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1. Jawaban Yosi2214
[tex]f(x) = 2x - 6 \\ g(x) = {x}^{2} - 9 \\ (fo \: g)(x) = f(g(x)) \\ = 2( {x}^{2} - 9) - 6 \\ = 2 {x}^{2} - 18 - 6 \\ = 2 {x}^{2} - 24 [/tex]
Kalau mau tau nilai x nya
2x^2-24=0
2x^2=24
X^2=24/2
X^2=12
X=akar dari 12
X=3, 46