Matematika

Pertanyaan

Sederhanakan bentuk cos (100°+ x) cos (10°-x)+ sin(100°+x) sin (10°-x)

1 Jawaban

  • cos(a-b)=cos a cos b + sin a sin b

    cos (100°+ x) cos (10°-x)+ sin(100°+x) sin (10°-x)
    a=100°+ x
    b=
    10°-x
    cos (100°+ x) cos (10°-x)+ sin(100°+x) sin (10°-x)
    =cos(100+x-(10-x))
    =cos(90+2x)
    =-sin 2x

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