Tentukan nilai X dan Y dengan metode substitusi, eliminasi dan matriks yang memenuhi fungsi linier: 1. 2X + 3Y = 16 dan X – 2Y = 4 2. 3X - 2Y = 6 dan X + Y = 4

1) x - 2y = 4 |×2
2x + 3y = 16
maka
2x - 4y = 8
2x + 3y = 16
------------------(-)
- 7y = - 8
y = 8/7
• x - 2y = 4 |×3
2x + 3y = 16 |×2
maka
3x - 6y = 12
4x + 6y = 32
-------------------(+)
7x = 44
x = 44/7
hp = ( 44/7 , 8/7 )

2) 3x - 2y = 6
x + y = 4 |×3
maka
3x - 2y = 6
3x + 3y = 12
------------------(-)
- 5y = - 6
y = 6/5
• 3x - 2y = 6
x + y = 4 |×2
maka
3x - 2y = 6
2x + 2y = 8
------------------(+)
5x = 14
x = 14/5
hp = ( 14/5 , 6/5 )

3) x - y = 16 |×4
4x + 2y = 28
maka
4x - 4y = 64
4x + 2y = 28
-------------------(-)
- 6y = 36
y = - 6
• x - y = 16 |×2
4x + 2y = 28
maka
2x - 2y = 32
4x + 2y = 28
------------------(+)
6x = 60
x = 10
hp = ( 10, - 6 )

4) x + 2y = 5 |×2
2x + 3y = 8
maka
2x + 4y = 10
2x + 3y = 8
------------------(-)
y = 2
• x + 2y = 5 |×3
2x + 3y = 8 |×2
maka
3x + 6y = 15
4x + 6y = 16
------------------(-)
- x = - 1
x = 1
hp = ( 1 , 2 )

5) x + 2y = 2
x - 2y = 2
-------------------(-)
4y = 0
y = 0
• x + 2y = 2
x - 2y = 2
----------------(+)
2x = 4
x = 2
hp = ( 2 , 0 )