Tentukan persamaan garis yg melalui titik (-2,-6) dan (8,14) !

y-y1/y2-y1 = x-x1/x2-x1
y-(-6)/14-(-6) = x-(-2)/8-(-2)
y+6/14+6 = x+2/8+2
y+6/20 = x+2/10
10(y+6) = 20(x+2)
10y+60 = 20x+40
10y = 20x+40-60
10y = 20x-20
y = 2x-2

*semoga membantu. sukses selalu ^_^