koordinat titik potong garis 4x+3y=7 dan 3x-2y=1 adalah jaw (1,1) cara kerja ?

titik potong 

4x  + 3y = 7..X3
3x  - 2y = 1 ..X4

12x + 9y = 21
12x - 8y = 4
...................(-)
17y = 17
y  = 1

4x + 3y = 7
4x + 3(1) = 7
4x = 4
x = 1

hp (x,y) = (1, 1)

4×+3y=7.×3

3×-2y=1.×4

12×+9y=21
12×-8y=1

17y=17
y=1

4×+3y=7
4×+3(1)=7

4×=4
×=1


(x,y)=1,1