f(x)=px+q f(1)=-5 f(-2)=3 f(t)=3 t=?

f(x) = px + q
f(1) = p + q = -5
f(-2) = -2p + q = 3
eliminasi
p + q = -5
-2p + q = 3
________-
3p = -8
p = -8/3
substitusi p = -8/3 ke -p + q = -5
maka diperoleh
-(-8/3) + q = -5
q = -5 - 8/3
q = -15/3 - 8/3
q = -23/3
fungsi f(x) = -8/3x - 23/3
untuk f(t) = 3
-8/3t - 23/3 = 3
-8/3t = 3 + 23/3
-8/3t = 9/3 + 23/3
-8/3t = 32/3
t = (32/3) (-3/8)
t = -4
t = -4