Matematika

Pertanyaan

bentuk sederhana dari (akar 3 + akar 7) (akar 3 - akar 7) / 2akar5 - 4akar2

2 Jawaban

  • (√3+√7)(√3-√7)/(2√5-4√2)
    = (3-7)/(2√5-4√2)
    = -4(2√5+4√2)/(2√5-4√2)(2√5+4√2)
    = -3(2√5+4√2)/(4.5-16.2)
    = -3(2√5+4√2)/(20-32)
    = -3(2√5+4√2)/-32
    = (3/32)(2√5+4√2)
  • ( √3 + √7 )( √3 - √7 )
    -------------------------------
    2√5 - 4√2

    = 3 - √21 + √21 - 7
    ----------------------------
    2√5 - 4√2

    = - 4
    --------------------
    2( √5 - 2√2)

    = - 2
    -----------------
    √5 - 2√2

    = - 2 ( √5 + 2√2)
    ------------------------
    (√5 - 2√2 )( √5 + 2√2)

    = - 2√5 - 2√2
    ---------------------
    5 - 2√10 + 2√10 - 8

    = - ( 2√5 + 2√2)
    ------------------------
    - 3

    = ⅓ ( 2√5 + 2√2 )

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