tentukan hasil operasi hitung dari [tex] \sqrt{50 } - 11 \sqrt{2} + 7 \sqrt{72} [/tex]

[tex]\sqrt{50 } - 11 \sqrt{2} + 7 \sqrt{72} \\ = \sqrt{25 \times 2} - 11 \sqrt{2} + 7 \sqrt{36 \times 2} \\ = 5 \sqrt{2} - 11 \sqrt{2} + 7 \times 6 \sqrt{2} \\ = (5 - 11 + 42) \sqrt{2} \\ = 36 \sqrt{2} [/tex]

Mapel : Matematika
Bab : Menyederhanakan Bentuk Akar

√50 - 11√2 + 7√72
= √25x2 - 11√2 + 7√36x2
= 5√2 - 11√2 + 42√2
= -6√2 + 42√2
= 36√2