diketahui fungsi f(x) = 1 - 2x dan (gof) = 4x2 - 6x + 3. tentukan a) g(x) b) (fog)3

f(x) = 1 - 2x
gof(x) = 4x² - 6x + 3

a)
g { f(x) } = 4x² - 6x + 3
g {1- 2x } = 4x² -6x + 3
g { x }  = 4 {1/2 (1- x)}² - 6{1/2 (1 - x)} + 3
g { x } = 4(1/4) (1 - x)² - 3 (1- x) + 3
g { x}  =  (1 - x)² - 3(1 - x) + 3
g { x} = 1 - 2x + x² - 3 + 3x + 3
g { x} =  x² + x  + 1

b)
f o g(3) = f { g(3)}
= f(3² + 3 +1)
= f(13)
= 1 - 2(13)
= 1 - 26
= - 25

JAWAB:
b. fog(x)=f(g(3))
= f(3^2+3+1)
= f(9+3+1)
= f(13)
=1-2(13)
= 1-26
= -25

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