simpangan baku dari data 3,4,5,5,6,7 adalah

= 3+4+2.5+6+7 / 6 = 5
1/6 [(3-5)²+(4-5)²+(5-5)²+(5-5)²+(6-5)²+(7-5)²] = 1/6 [(4 + 1 + 0 + 0 + 1 + 4)]
1/6 x 10 = 10/16
S = √S² = √10/16 =√5/8

[tex]s = \sqrt{ \frac{1}{6} ((3 - 5) ^{2} +(4 - 5) ^{2} +(5 - 5) ^{2} +(5 - 5) ^{2} +(6 - 5) ^{2} +(7 - 5) ^{2} } \\ = \sqrt{ \frac{1}{6} (4 + 1 + 0 + 0 + 1 + 4)} \\ = \sqrt{ \frac{1}{6} \times 10} \\ = \sqrt{ \frac{5}{3} } \\ = \frac{ \sqrt{5} }{ \sqrt{3} } \\ = \frac{1}{3} \sqrt{15} [/tex]