Tolong jawab 1 - 15 pake cara plissss

^ = pangkat
/ = dibagi atau per

1) f(x) = (3x + 2)^4
= 4 ( (3x + 2)^4 - 1 ) × 3
= 12 (3x + 2)³

2) f(x) = (5 - 2x) ^5
= 5 ( (5 - 2x) ^5 - 1) × -2
= -10 (5 - 2x)^4

3) (4x - 6)^ ½
= ½ ( (4x - 6)^ ½ - 1) × 4
= 2 (4x - 6)^-½
= 2 / √(4x - 6)

4) 3(2x² + 5)^ 6
= 3 × 6 ( (2x² + 5)^ 6 - 1) × 4x
= 72x (2x² + 5)^ 5

5) 4(3 - x³)³
= 4 × 3 ( (3 - x³) ³ - ¹) × -3x²
= -36x² (3 - x³) ²

6) (6x² - 5x + 4)^7
= 7 ( (6x² - 5x + 4)^ 6 ) × 12x × -5
= -420x (6x² - 5x + 4)^ 6

7) √(2x^4 + 5)
= (2x^4 + 5) ^½
= ½ ( (2x^4 + 5)^- ½) 8x³
= 4x³ (2x^4 + 5)^ -½)
= 4x³ / √(2x^4 + 5)

8) sin (5x - π)
= cos (5x - π) × 5
= 5 cos (5x - π)

9) 3 cos (2x + π)
= 3 (- sin (2x + π) ) × 2
= -6 sin (2x + π)

10) 2 cos (2π - 3x)
= 2 (-sin (2π - 3x) ) -3
= 6 sin (2π - 3x)

11) 4 sin (π - 5x²)
= 4 (cos (π - 5x²) ) × -10x
= -40x cos (π - 5x²)

12) sin ^4 2x
= 4 (sin^3 2x) ( cos 2x) × 2
= 8 sin^3 2x cos 2x

13) cos ^5 3x
= 5 (cos ^4 3x) (-sin 3x) 3
= -15 cos^4 3x sin 3x

14) 5 sin ^7 (2x - π)
= 5 × 7 sin^ 6 (2x - π) cos (2x - π) × 2
= 70 sin^6 (2x - π) cos (2x - π)

15) 6 cos³ (π - 2x)
= 6 × 3 cos² (π - 2x) (- sin (π - 2x)) × -2
= 36 cos² (π - 2x) sin (π - 2x)