Matematika

Pertanyaan

Diberikan persamaan x2+y3= x+1. Tentukan turunan dy/dx dan d2y/dx2

1 Jawaban

  • jawab

    x² + y³ = x+ 1
    y³ = - x²  + x + 1

    y = (- x² + x + 1)^(1/3)

    dy/dx =  1/3 (- x² + x + 1)^(-2/3 . (-2x + 1)
    dy/dx = 1/3 (-2x +1) (-x² + x + 1)^(-2/3)
    dy/dx = (-2/3 x + 1/3)(-x² + x + 1)^(-2/3)

    d2y/dx2 = (-2/3)(-x² + x +1)^(-2/3) + (-2/3 x + 1/3)(-2/3)(-x^2+x +1)^(-5/3) (-2x +1)


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