Matematika

Pertanyaan

No 1, 2, 3 dong.... dengan caranya ya.... ☺️
No 1, 2, 3 dong.... dengan caranya ya.... ☺️

2 Jawaban

  • 1) (243²)^-1/5

    = ( ( 3^5)²)^-1/5

    = (3^10)^-1/5

    = 3-²

    = 1/3²

    = 1/9 ( B )

    2) 3√75 + 4√12 - 5√48
    = 3•5√3 + 4•2√3 - 5•4√3
    = 15√3 + 8√3 - 20√3
    = 3√3 ( C )

    3) ( 6 / √7 - 2) × ( √7 + 2 / √7 + 2 )

    = 6 ( √7 + 2 )
    ------------------------------
    ( √7 - 2)(√7 + 2 )

    = 6 ( √7 + 2 )
    ------------------------------
    7 - 2√7 + 2√7 - 4

    = 6 ( √7 + 2 )
    --------------------
    3

    = 2( √7 + 2)

    = 2√7 + 4 ( D )
  • Mohon best solution yah :)
    Gambar lampiran jawaban imamjhe