tentukan penyelesaian dari [tex] \frac{(x + 4)}{4} - \frac{(3x - 4)}{7} < \frac{1}{2} [/tex] tolong ya! ^^

lngsung jawab yyaa
=[tex] \frac{7(x+4)}{28}- \frac{4(3x-4}{28} [/tex]<[tex] \frac{1}{2} [/tex]
=[tex] \frac{7x+28}{28} - \frac{12x-4}{28} [/tex]<[tex] \frac{1}{2} [/tex]
=[tex] \frac{7x+28-12x+4}{28}[/tex]<[tex] \frac{1}{2} [/tex]
=[tex] \frac{-5x+24}{28} [/tex]<[tex] \frac{1}{2} [/tex]
=2(-5x+24)<28.1
=-10x+48<28
=-10x<[tex] \frac{28/}{48} [/tex]
=-10x<[tex] \frac{1}{2} [/tex]
=-20x<1