Matematika

Pertanyaan

[tex] \lim_{x \to 1} \frac{2( x^{2} -4)}{x-2} - \frac{ x^{2} -2x}{2(x-2)} =?

[/tex]

1 Jawaban

  • [tex] \frac{2 x^{2} -8}{x-2}- \frac{ x^{2} -2x}{2x-2} = \frac{2. 1^{2}-8 }{1-2}- \frac{ 1^{2}-1.2 }{2.1-2}= \frac{-6-1}{-1-0}= \frac{-7}{-1}=7 [/tex]

    belum pasti hehe

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