Matematika

Pertanyaan

volume benda putar kurva y=x^2 garis y=2x kuadran 1 diputar 360°

1 Jawaban

  • y = x²
    y = 2x

    x² - 2x= 0
    x(x  - 2 ) = 0
    x  = 0
    x = 2

    V = π (0..2) ∫ (2x)² - (x²)² dx
    V = π (0..2) ∫ ( 4x² - x⁴) dx
    V = π  [ 4/3 x ³ - 1/5 x⁵] (2..0) 
    V = π [ 4/3 (8) - 1/5 (32)]
    V = π [  32/3 - 32/5]
    V = 64/15 π

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