Harga 3 pasang sepatu dan 2 tas adalah...

sepatu misal = s
tas misal =t
3s+5t = 290.000 (×4) 12s+20t = 1.160.000
4s+2t = 200.000 (×3) 12s+6t = 600.000
________________ _
14t = 560.000
t = 40.000
t=40.000 di sub ke persamaan 2

4s+2×40.000 = 200.000
4s+80.000 = 200.000
4s = 200.000-80.000
4s = 120.000
s = 30.000


maka harga 3pasang sepatu + 2 tas

3s+2t =
3×30.000 + 2×40.000 =
90.000 + 80.000 = 170.000

maka jawabannya yg c 170.000

3x+ 5y = 290.000 --- pers.1
4x+2y= 200.000 --- pers 2

Pers 1 dikali 4
Pers 2 dikali 3

12x+ 20y = 1160000
12x+6y = 600.000
------------------------------ -
14y = 560000
y= 40.000

Pers 1 dikali 2
Pers 2 dikali 5

6x+ 10y = 580.000
20x+ 10y= 1.000.000
-14x = -420.000
x= 30.000

3 pasang sepatu dan 2 tas =

3(30.000)+ 2(40.000)
90.000+ 80.000 = 170.000 ( C )