persamaan logaritma 3 pangkat log ( x + 6) - 3 pangkat log ( x - 2) = 2 tolong bantuannya!!

Bab Logaritma
Matematika SMA Kelas X

^ = pangkat

^3log (x + 6) - ^3log (x - 2) = 2
^3log ((x + 6)/(x - 2)) = 2
(x + 6)/(x - 2) = 3²
x + 6 = 9 (x - 2)
x + 6 = 9x - 18
x - 9x = -18 - 6
-8x = -24
x = (-24) : (-8)
x = 3

syarat
x + 6 > 0
x > -6

x - 2 > 0
x > 2

maka, x = 3