tentukan persamaan garis yang melalui titik a (11,-1) dan (8,5) b. (1,1) dan (9,9)

y - y1/y2 - y1 = x - x1/x2 - x1
a. (11,-1) & (8,5)
y - (-1)/5 - (-1) = x - 11/8 - 11
y + 1/ 5 + 1 = x - 11/8 - 11
y + 1/6 = x - 11/-3
(dikalikan silang)
6(x - 11) = -3(y + 1)
6x - 66 = -3y - 3
6x + 3y = -3 + 66
6x + 3y = 63
b. (1,1) & (9,9)
y - 1/9 - 1 = x - 1/9 - 1
y - 1/8 = x - 1/8
(dikalikan silang)
8(y - 1) = 8(x - 1)
8y - 8 = 8x - 8
8y - 8x = -8 + 8
8y - 8x = 0