integral 8x(x^2+6)^2 =

InTegraL

Misal :
u = x² + 6
du/dx = 2x
2x dx = du
4 . 2x dx = 4 du
8x dx = 4 du

∫8x(x² + 6)² dx
= ∫u² 4du
= 4/3 u³ + C
= 4/3 (x² + 6)³ + C ✔