16&17) hambatan pengganti dari rangkaian hamabatan di atas sebesar??

[tex]17. \\ \frac{1}{8 + 12} + \frac{1}{10 + 20} + \frac{1}{60} \\ = \frac{1}{20} + \frac{1}{30 } + \frac{1}{60 } \\ = \frac{3}{60} + \frac{2}{60} + \frac{1}{60} \\ = \frac{6}{60} = \frac{60}{6} = 10 \\ \\ 40 + 10 + 20 = 100(c)[/tex]

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