persamaan garis yang melalui titik (4,-1) dan sejajar garis 2x-10y=3 adalah

2x - 10y = 3
m1 = -a/b
m1 = -2/-10
m1 = 1/5
m1 = m2 = 1/5
y - y1 = m(x - x1)
y - (-1) = 1/5(x - 4)
5(y + 1) = 1(x - 4)
5y + 5 = x - 4
5y - x = -4 - 5
5y - x = -9 atau
5y - x + 9 = 0

ax + by = c, sejajar, (p,q)
ax + by = ap + bq

2× - 10y = 3, sejajar, (4, -1)
2× - 10y = 2 . 4 - 10 . (-1)
2× - 10y = 8 + 10
2× - 10y = 18

x - 5y = 9


semoga bermanfaat